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[Webby the Bear]

Or simply put 5 litres less fuel in to compensate when you fill up

Oh, and stop fretting

Not frettin' Al. you know I like to put my crazy thoughts down on OOF so you can all mock me help me find the answers 

I would never mock you, Steve....as you know.

 

[cem_devecioglu]

Webby you can loose 30-35 kgs at most .. this may impact acceleration less than 0.1 secs on a 1700 kg car..


so not worth it..  but if you want loose weight for health reasons, do it very very  slowly




ps: now calculated it actually effects 0.15 secs  

[Webby the Bear]

Webby you can loose 30-35 kgs at most .. this may impact acceleration less than 0.1 secs on a 1700 kg car..


so not worth it..  but if you want loose weight for health reasons, do it very very  slowly




ps: now calculated it actually effects 0.15 secs

haha! thanks cem.

care to share the formula / calculation with the class?

[cem_devecioglu]

Webby you can loose 30-35 kgs at most .. this may impact acceleration less than 0.1 secs on a 1700 kg car..


so not worth it..  but if you want loose weight for health reasons, do it very very  slowly




ps: now calculated it actually effects 0.15 secs

haha! thanks cem.

care to share the formula / calculation with the class?

easy.. no need to go in detailed calculations since f=m*a




assume your engine with X force  accelerates a 1700 kg car in 9 secs from 0 to 100km/h ..


then 30/1700= 0.0176 then


9*0.0176=0.1584 secs

[Webby the Bear]

Spot on Cem. That's answered my question precisely! 

[The Sheriff]

Webby you can loose 30-35 kgs at most .. this may impact acceleration less than 0.1 secs on a 1700 kg car..


so not worth it..  but if you want loose weight for health reasons, do it very very  slowly




ps: now calculated it actually effects 0.15 secs

haha! thanks cem.

care to share the formula / calculation with the class?

easy.. no need to go in detailed calculations since f=m*a




assume your engine with X force  accelerates a 1700 kg car in 9 secs from 0 to 100km/h ..


then 30/1700= 0.0176 then


9*0.0176=0.1584 secs

You lost me after 'assume' .....

[symes]

Webby you can loose 30-35 kgs at most .. this may impact acceleration less than 0.1 secs on a 1700 kg car..


so not worth it..  but if you want loose weight for health reasons, do it very very  slowly




ps: now calculated it actually effects 0.15 secs

haha! thanks cem.

care to share the formula / calculation with the class?

easy.. no need to go in detailed calculations since f=m*a




assume your engine with X force  accelerates a 1700 kg car in 9 secs from 0 to 100km/h ..


then 30/1700= 0.0176 then


9*0.0176=0.1584 secs

You lost me after 'assume' .....

STMO what that means mate is----for every 20 boxes boxes of Dunkin Donuts you eat-you need to fit a bigger engine---got it now mate

[The Sheriff]

Got it


Or you could buy a Chevrolet Orlando, 0-60 in three minutes, no matter what you're carrying.

[symes]

or an omega v6 with a shot coil pack--0-60 in your having a laugh

[05omegav6]

or an omega v6 with a shot coil pack--0-60 in your having a laugh

Getting to 60 is only a secondary concern...

The biggest worry is getting the engine to rev fast enough to be able to change in to second...

[Broomies Mate]

Webby you can loose 30-35 kgs at most .. this may impact acceleration less than 0.1 secs on a 1700 kg car..


so not worth it..  but if you want loose weight for health reasons, do it very very  slowly




ps: now calculated it actually effects 0.15 secs

haha! thanks cem.

care to share the formula / calculation with the class?

easy.. no need to go in detailed calculations since f=m*a




assume your engine with X force  accelerates a 1700 kg car in 9 secs from 0 to 100km/h ..


then 30/1700= 0.0176 then


9*0.0176=0.1584 secs

Sorry Cem, but this is the biggest load of ball-sacks. 

We are not in a pristine physics lab, where everything is cleaner than the Pope's Penis.  This is the real world.  The mass of a vehicle doesn't change in a linear manner.

I have no doubt you have an excellent understanding of Physics, but you cannot apply simplistic equations to this type of scenario!  There are just too many variables. 

[cem_devecioglu]

Webby you can loose 30-35 kgs at most .. this may impact acceleration less than 0.1 secs on a 1700 kg car..


so not worth it..  but if you want loose weight for health reasons, do it very very  slowly




ps: now calculated it actually effects 0.15 secs

haha! thanks cem.

care to share the formula / calculation with the class?

easy.. no need to go in detailed calculations since f=m*a




assume your engine with X force  accelerates a 1700 kg car in 9 secs from 0 to 100km/h ..


then 30/1700= 0.0176 then


9*0.0176=0.1584 secs

You lost me after 'assume' .....

 




STMO , you know I'm an engineer..  actually for reservoir and drilling area.. in my graduation subject for a very precise calculation many parameters are necessary and most of the times obtaining those parameters cost multi million $$$..  so in our exams our teachers were giving us questions with missing parameters that we had to assume but by derivation from other parameters actually a logical range.. as nothing is fix (usually)..


and to solve those questions you need to use numerical analysis methods on a range which requires computer programming..


so we initiate the programs on some logical assumptions get the results then compare from other wells/reservoirs historical data..  and  if somethings wrong we re-try.. actual measurements in those areas are done after we reach some depth or we complete multi drill areas which costs some dear money..




now you get the picture .. in this case of acceleration for a rough calculation actual force is not necessary.. but if you wanted a near exact calculation


you need to know  temperature, engines wear, engines ideal force (or hp) , wind speed and direction, tyres friction coef.. etc etc etc


of course simplest answer will be to accelerate the car with Webby and later with a person with 30 kgs less and measure the time

[cem_devecioglu]

of course time measurements can not be done by bare hand.. you need a device set up

[cem_devecioglu]

Webby you can loose 30-35 kgs at most .. this may impact acceleration less than 0.1 secs on a 1700 kg car..


so not worth it..  but if you want loose weight for health reasons, do it very very  slowly




ps: now calculated it actually effects 0.15 secs

haha! thanks cem.

care to share the formula / calculation with the class?

easy.. no need to go in detailed calculations since f=m*a




assume your engine with X force  accelerates a 1700 kg car in 9 secs from 0 to 100km/h ..


then 30/1700= 0.0176 then


9*0.0176=0.1584 secs

Sorry Cem, but this is the biggest load of ball-sacks. 

We are not in a pristine physics lab, where everything is cleaner than the Pope's Penis.  This is the real world.  The mass of a vehicle doesn't change in a linear manner.

I have no doubt you have an excellent understanding of Physics, but you cannot apply simplistic equations to this type of scenario!  There are just too many variables. 

physic equations are valid.. those extra pamaters will change some fractions.. but I doubt even you can measure 0.15 secs easily

[Broomies Mate]

physic equations are valid.. those extra pamaters will change some fractions.. but I doubt even you can measure 0.15 secs easily

The equations are valid.  They have no validity in this scenario, though.